Listed below are mostly Craps Pit visitor submitted systems*.
Have your system added to the list by e-mailing me at starchip@live.com

Best Odds Craps Casinos in Las Vegas Casino Royale Craps on the Strip. The Casino Royale on the Las Vegas Strip offers 100X odds on their two craps tables. Their betting limits at the craps table range from a minimum bet of $3 to a maximum bet of $500, and the maximum odds bet you can place is $2500 per bet. There are, of course, ways in which the craps enthusiast could turn things around and make the best of the situation when placing a Put bet and this happens when the house actually brings good odds. For instance, if the casino brings a 50x odds to the table, placing a Put bet could end up having a lower house edge when compared to a Place bet. Normal Craps Bets and Payout Odds As you can see from the payout table, there are many bets that sound exotic and arcane but they really aren't that good, even though they may sound like the 'secret' bets that no one knows about. Really the only good ones are the pass line or don't pass in conjunction with the free odds bets. Overall, the Odds bet is the true economic engine for successful craps players, especially because players can “turn off” the wager at any time of their choosing. A sharp craps specialist can seamlessly alternate between turning their Odds bets on and off to take advantage of table conditions, all without being forced to fade an iota of. For example, “3-4-5x Odds,” usually means you can bet 3x Odds on the 4 or 10, 4x Odds on the 5 or 9, and 5x Odds on the 6 or 8. Check out some great online casinos such as Sunpalace, Casino Max, or slotsplus.

For all even-money betting.
System betting means you're using a specific strategy in trying to be a winner. However, in the long-run, the odds favor the casino and no system can change that fact. That is not to say systems can't work beautifully in the short term.
What makes the 1 - 3 - 2 - 6 System attractive is that you risk only two betting units for a chance to win ten units. You can make a nice profit with a minimal investment.
The first bet is one unit, if you win, add another unit, making the second bet a total of three units.
If you win the second bet, there are 6 units on the table. Remove four units, making your third bet two units.
If it wins add two more units, making it a total of six units for your fourth bet.
If the fourth bet wins you'll collect a total of 12 units, of which ten units are profit!
If you lose the first bet, the loss is one unit. Assuming you win the first, but lose the second bet, your net loss is two units.
If you win the second, but lose the third bet, you have a profit of two units.
If you win the first three bets but lose the fourth bet, you'll break even.
If you lose the second bet five out of six times and win four consecutive bets once, you'll be right back to even.
Use this system for even-money betting at any game.
Good Luck!
If you would like to explore other, more serious systems, and/or investigate my SUPERIOR ROULETTE
SYSTEM at http://www.letstalkwinning.com/roulys.htm.
Thank you. Tony R Frank
www.letstalkwinning.com
www.gambleclicks.com

Another explanation of the same system:

The 1-3-2-6 System
The name of this system says it all. It is based on the premise that you can win four times in a row.
Your initial bet is 1 unit, the second 3 units, the third 2 units and the fourth 6 units.
Let's assume that each unit is $10 and the odds are 1:1 - even money.
( 1 ) The first bet is $10. ( you win )
they pay you $10 + $10=$20 you add $10 more off your money making the second bet $30 you now have $20 of your money at risk plus $10 of casino money
( 2 ) When winning again on the second bet, there would be $60 on the table Of this you take down $40
$30 + $ $30 = $60 -$40 = $20
( 3 ) The third bet is $20. The third bet wins, you will have $40 on the table to which you add $20 making a total of $60 for the fourth bet.
$20 + $20 =$40 +$20= $60
If the fourth bet wins, there would be a total of $120, of which $100 is net profit.
$60 + $60 = $120 - $20 = $100 profit
Now all the bet with the profit is taken down and you start the system all over again at $10.
If you lose the first bet, your loss is $10.
The second level loss is $20.
At the third level, a loss will give you a net profit of $20.
At the fourth level, a loss leaves you breaking even.
Each time you lose, you start all over again at $10.
The attraction of this system is that you risk $20 at a chance of making $100 net profit. This means you can lose five times, and with one win get your money back
bigkahnman@aol.com

This is a mixture of Martingale and Insurance systems. Bets are raised one unit after each losing bet and lowered one unit after each winning bet. The sequence and amount raised or lowered can be varied to suit particular games and odds.
System description courtesy of Advice + resources Gambling Guide. Learn how to win. Casino games and sports. Find it here: directory, online casinos, free-play games, news, and much more.

Craps Bets Odds Payouts

Fibonacci progression 0,1,1,2,3,5,8,13,21,34,55, etc.
Where each number is a sum of the previous two numbers.
Basic idea is to get two wins in a row.
For each loss, step up one in the progression.
For each win, make the same bet again.
If win again, start progression over. If lose, advance one step.
Unknown contributor.
BTW, in the fibonacci you don't need 2 wins in row to begin again.....WLW also gives you a win on the series. Kayjay
This is a good system as WLW shows a profit. However, I would add the following:
If PASS just won, bet on PASS. If DON'T PASS won, bet on D.P.
Play the winning side and you will catch any streak of wins. This will work on Craps, Roulette, Baccarat. James T Mays

A betting method to apply to all systems.
We all have losing bets and when we lose we want to recoup that money. Some try the Martingale. i.e. 1-2-4-8-16, etc. Seasoned players know this is a sure way to leave the table broke and with an attitude.
Try the Knockdown instead.
When you lose a one unit bet replace it with only one unit the first go. Then your progression will be 1-1-3-6-12, etc., ( I strongly suggest ending at 3 ) not 1-2-4-8-16, etc., as in a Martingale.
You still always win except on the second bet where you break even. We long time players know how to appreciate being even.
Over time this practice can improve most systems by several percentage points.

This system is also called the 'Cancellation' system. There are many variations. In its simplest form, you write down a series or a set of numbers; say, 1 2 3 4 5 6. The series can be short or long and not necessarily sequential such as 1 1 1 3 3 5 7. The choice of a particular series depends on the type of game you want to apply it to and the odds of the bet.
Each number represents the amount in units or chips to bet. You bet the first and last of these numbers. In this example 1 and 6, which totals 7 units.
If you win, you cross out the two numbers and bet the next two 'ends' (the outside numbers). In this instance 2 and 5. If you win again you bet on the next two remaining numbers 3 and 4, and if you win that too, you would have made a 'coup' or completed one game. Then you start all over again.
If you lose, then you add that one number to the end of the series. Say you lost your first bet of 7 units (1+6). Then you add number 7 to the end of the series to look like this: 1 2 3 4 5 6 7 and your next bet would be 8 units ( 1+7). If you won the first bet but lost the second 2 and 5, then the series of numbers would look like this: 2 3 4 5 7.
If you work it out, you will see that when the series is completed or when you make a 'coup', there is always a profit. The negative side of this system is that you could end up betting large sums of money even if your initial bet is small.
System description courtesy of Advice + resources Gambling Guide. Learn how to win. Casino games and sports. Find it here: directory, online casinos, free-play games, news, and much more.

The Martingale system is a very old and extremely simple system. It is based on the probability of losing infinite times in a row and is usually applied to 'even money' bets.
You start with one bet. If you win, you start again with one bet. If you lose, you double your bet. Each time you lose, you double your last lost bet. Eventually you are bound to win. When you win you would recover all your lost bets plus one unit (or chip) profit against your initial wager.
Although infallible in theory, the Martingale system requires a large bankroll, has a very low return and is a very risky one because of the maximum bet limits imposed by the casinos. If you run out of money or reach the house limit, you can lose a lot with no chance to recover your losses.
System description courtesy of Advice + resources Gambling Guide. Learn how to win. Casino games and sports. Find it here: directory, online casinos, free-play games, news, and much more.

This system is similar to the Paroli system and has the effect of 'pyramiding' your profit. Pyramiding is a parlay wager whereby the original wager plus its winnings are played on successive wagers.
It is commonly used in horse racing betting. Basically you make a bet and if you win you re-invest the winnings on the next bet. You 'let it ride'.
This method of play is by no means risk free, but it offers the least amount of risk of all wagers since the player is only concerned with either a win, place or show selection or a combination of the three.
It is one of the oldest methods of wagering and was originally derived from the same premise that banking systems use to compound interest.
System description courtesy of Advice + resources Gambling Guide. Learn how to win. Casino games and sports. Find it here: directory, online casinos, free-play games, news, and much more.

This system is in a way the opposite of the Martingale system. You start with one bet and you increase your bet when you win rather than when you lose.
However, you will need to plan a betting procedure whereby you know how far you will let the bet build before you take it down to the initial starting bet and how much to raise after each win. This obviously depends on the type of game played and the odds of the bet.
The advantage of this system is that you do not require a large bankroll. It lets the profit run and cuts short the losses.
System description courtesy of Advice + resources Gambling Guide. Learn how to win. Casino games and sports. Find it here: directory, online casinos, free-play games, news, and much more.

Pass / Don't pass betting progression
This system was first featured by Gil Stead in the 1980's newsletter THE CRAPSMEN.
First, you need 26 checks, all same denomination($1,$5,etc.). Take the first check (Bet A) and wager it on either Pass Line or Don't Pass Line.
If this bet is won, parlay it and wager both bet and win, or two units.
This is the heart of the system: one MUST back bet or parley the win.
Now if you are favored with a second win, you will of course be ahead.
Take your three extra checks and place them in the back (lock up) chip rack and start over again with one check.
Betting progression is as follows: 1,1,1,2,2,3,4,5,7 (26 checks total).
Example: Bet A (1check): lost
Bet B (1check): lost
Bet C (1check): lost
Bet D (2checks): won
Bet E parlay (2 checks plus 2 checks won): won.
You're now ahead by two checks (28 checks total). Start over again with a one check bet.
Think about it.You have a total of nine opportunities (consecutive) before you limit your losses.You don't ever have to limit your winnings.
Richard G. Poirier

Pass / Don't Pass Odds progression
This system progresses odds bets on either the Pass Line or Don't Pass based on the value of a running count.
Keep track of the count as follows:
A point that passes counts as +3
A point that misses counts as -2
Naturals and craps count as 0. If the count exceeds 55 or -37 then the progression is lost and started over.
Anytime the odds bets show a net profit, the progression is started over.
Michael

I win over and over playing this way. Please look it over.
I'm looking for your comments good or bad. Please post or e-mail them to me.
Have I developed THE winning system { the one that overcomes the odds ad puts the odds in the players favor } or have I just been getting lucky?
SYSTEM:
STREAKS -
Streaks of P and DP happening in a row, odds for each streak to continue are 50% less than the last streak.
EXAMPLE :
[ all examples will only go to a level of ten - P or DP occurring in a row - the math is the same no matter how far or near I take it - IT can not change ]
10 in a row - will occur __1 time
09 in a row - will occur __2 times
08 in a row - will occur __4 times
07 in a row - will occur __8 times
06 in a row - will occur _16 times
05 in a row - will occur _32 times
04 in a row - will occur _64 times
03 in a row - will occur 128 times
02 in a row - will occur 256 times
01 in a row - will occur 512 times
Streaks of P and DP - 2036 total decisions
50% will be P and 50% will be DP.
Doubling your bet after a loss.
No matter where you end your doubling a bet after a loss you will lose.
EXAMPLE :
[ ending the doubling and taking a loss at 5 losing wagers in a row ]
Wagers
01 unit__ win = plus 1 unit_ lose = -1 unit then wager
02 unit__ win = plus 1 unit_ lose = -3 units then wager
04 unit__ win = plus 1 unit_ lose = -7 units then wager
08 unit__ win = plus 1 unit_ lose = -15 units then wager
16 unit__ win = plus 1 unit_ lose = -31 units
END
So playing the OPPOSITE of the prior decision, this is what will happen:
All streaks of
01 in a row-plus 1 unit
02 in a row-plus 1 unit
03 in a row-plus 1 unit
04 in a row-plus 1 unit
05 in a row minus 31 units
06 in a row minus 31 units
07 in a row minus 31 units
08 in a row minus 31 units
09 in a row minus 31 units
10 in a row minus 31 units
What happens when we look at the amount of streaks we will get when we play.
__1 streak of 10 in a row = minus _31 units 1x-31
__2 streaks of 9 in a row = minus _62 units 2x-31
__4 streaks of 8 in a row = minus 124 units 4x-
__8 streaks of 7 in a row = minus 248 units 8x-31
_16 streaks of 6 in a row = minus 496 units 16x-31
_32 streaks of 5 in a row = minus 992 units 32x-31
_64 streaks of 4 in a row = plus ___64 units 64x 1
128 streaks of 3 in a row = plus __128 units 128x 1
256 streaks of 2 in a row = plus __256 units 256x 1
512 streaks of 1 in a row = plus __512 units 512x 1
for a total of plus 960 units minus - 1953 units = minus - 993 units
As you can see betting on the opposite decision [ P / DP ] and doubling each losing wager until you win WILL lose you money.
Playing BOTH sides P and DP at the same time.
Play both sides at the same time increasing the wager on the side of P / DP that you have just lost a wager on and using the side that you won a wager on as a BACK UP BET.
HOW:
Start by placing 1 unit on P AND DP [at the same time] then which ever side WINS place a wager of one unit and on the side that LOST place a wager of 2 units.
If the side with 2 units wins your ahead 1 unit then place 1 unit on the winning side and go up to 2 units on the side that lost, the one that only had 1 unit on it.
If the side that had 2 units on it lost keep only 1 unit on the winning side but increase your wager on the losing side up to 3 units.
If the side that has the 3 units on it wins and the side with 1 unit loses you are ahead 1 unit, so place 1 unit on the side that won and 2 units on the side that lost.
If the side with 3 units on it loses and the side with 1 unit wins keep one unit on the side that won and increase your wager on the losing side up to 5 units.
If the side with 5 units on it wins you are up 1 unit . Place 1 unit on the winning side and increase the losing side up to 2 units.
If the side with 5 units on it loses keep 1 unit on the side that won and increase your wager up to 9 units on the losing side.
If the side with 9 units on it wins you are up 1 unit . Place 1 unit on that winning side and increase the unit on the losing side up to 2 units.
If the side with 9 units loses we STOP HERE AND TAKE OUR LOSS! We are only down 15 units NOT 31 units like we would be after 5 losses in a row if we were only playing ONE SIDE [ P or DP ] and doubling our wager after each loss.
WE ARE DOWN LESS THAN 50% of what we could be, talk about minimizing losses.
EXAMPLE: P wins then DP wins
__P____DP__
__1____1___ wager/ P wins DP loss= even
__1____2___ wager/ P lost DP wins= plus 1 unit
EXAMPLE: P wins P wins DP wins
__P____DP__
__1____1___ wager/ P wins DP lost= even
__1____2___ wager/ P wind DP lost= minus 1 unit
__1____3___wager/ P lost DP wins= plus 1 unit
EXAMPLE: P wins P wins P wins DP wins
__P____DP__
__1____1___ wager/ P wins DP lost= even
__1____2___ wager/ P wins DP lost= minus 1 unit
__1____3___ wager/ P wins DP lost= minus 3 units
__1____5___wager/ P lost DP wins = plus 1 unit
EXAMPLE: P wins P wins P wins P wins DP wins
__P____DP___
__1____1____wager/ P wins DP lost= even
__1____2____wager/ P wins DP lost= minus 1 unit
__1____3____wager/ P wins DP lost= minus 3 units
__1____5____wager/ P wins DP lost= minus 7 units
__1____9____wager/ P lost DP wins= plus 1 unit
EXAMPLE: P wins P wins P wins P wins P wins [ followed by a P or DP it will not make a difference -this is where we end our losing streak]
__P____DP___
__1____1____wager/ P wins DP lost= even
__1____2____wager/ P wins DP lost= minus 1 unit
__1____3____wager/ P wins DP lost= minus 3 units
__1____5____wager/ P wins DP lost= minus 7 units
__1____9____wager/ P wins DP lost= minus 15 units
END
EXAMPLE: P wins DP wins DP wins P wins P wins P wins DP wins P wins P wins DP wins.
P-DP-DP-P-P-P-DP-P-P-DP
********************************
__P____DP___
__1____1____wager/ P wins DP lost= even
__1____2____wager/ P lost DP wins= plus 1 unit
__2____1____wager/ P lost DP wins= even
__3____1____wager/ P wins DP lost= plus 2 units
__1____2____wager/ P wins DP lost= plus 1 unit
__1____3____wager/ P wins DP lost= minus 1 unit
__1____5____wager/ P lost DP wins= plus 3 units
__2____1____wager/ P wins DP lost= plus 4 units
__1____2____wager/ P wins DP lost= plus 3 units
__1____3____wager/ P lost DP wins= plus 5 units
Playing this way seems to work for every streak of P or DP 1-2-3 or 4 in a row your ahead 1 unit and for every streak of 5 or more you are down 15 units.
Let us look at what will happen in the long term [run] . When we look at the amount of streaks we will get.
Streaks of P and DP :
01 in a row = plus 1 unit
02 in a row = plus 1 unit
03 in a row = plus 1 unit
04 in a row = plus 1 unit
05 in a row = minus 15 units
06 in a row = minus 15 units
07 in a row = minus 15 units
08 in a row = minus 15 units
09 in a row = minus 15 units
10 in a row = minus 15 units
amount of streaks 50% P and 50% DP
Streaks of - in a row
01__512 ----- plus 512
02__256 ----- plus 256
03__128 ----- plus 128
04___64 ----- plus 64
total for streaks 1-4 = plus 960 units
******************************************
05__32 ----- 32 x minus 15 units = minus 480
06__16 ----- 16 x minus 15 units = minus 240
07___8 ----- 8 x minus 15 units = minus 120
08___4 ----- 4 x minus 15 units = minus 60
09___2 ----- 2 x minus 15 units = minus 30
10___1 ----- 1 x minus 15 units = minus 15
total for streaks 5-10 = minus 945 units
*************************************************
Grand total plus 960 units - minus 945 units = plus 15 units
That seems like a lot of work just for 15 units not to talk about the time that would take, but think about this will you really bust at 15 units every time? Will the method of play really go like this win 15 units then lose 15 units lose 15 units win 15 units and break even. NO. When you bust 15 units you have to ADD the amount of units you won to get the TRUE amount of the bust. Say you won 12 units and then bust 15 units your TRUE bust is only 3 units or say you won 22 units and then bust 15 units your TRUE bust is really a win of 7 units.
So in a 50/50 game [ craps ] you have to look at what the average is in the long run and that is your average bust WILL only be 7 1/2 [ 8 ] units playing this way and your average win will be 7 1/2 [ 8 ] units. Now the great part.
Play what is called a 2-1-2-1 bankroll money management strategy along with what I have just shown you and you can not lose
A 2-1-2-1 strategy is easy what you do is break ALL your play into segments and win or lose you leave after a segment and take a break and return later to start another segment.
But here is how you play each segment.
Bankroll required
You need 30 units- each unit MUST be at least the table minimum bet [ example; at a $ 1.00 table you need $ 30.00 at a $ 5.00 table you need $150.00 ] per segment to be played also you NEED to be able to play AT LEAST 3 segments
Start segment one by playing the 1-2-3-5-9-unit progression with DOUBLE the wager progression. Play 2-4-6-10-18 with 2 units on the other side as your back-up wager. Play this way until you win 30 units or bust [ your average bust will be 50 % of segment money- 15 units ] .IF YOU WIN 30 UNITS: walk away and take a break or find another table to play at.
When you return to play this time [ your 2nd segment ] Play 1-2-3-5-9 unit progression with 1 unit as your back-up wager. IF YOU BUST : start over playing 2-4-6- 10-18 unit progression with a 2 unit back-up wager again.
EVERY TIME YOU BUST START OVER WITH THE 2-4-6-10-18 PROGRESSION WITH THE 2 UNIT BACK-UP WAGER.
EVERY TIME YOU WIN 15 UNITS ON YOUR 2ND SEGMENT START OVER PLAYING THE 2-4-6-10-18 PROGRESSION WITH A 2 UNIT BACK-UP WAGER.
So when you are playing the 2-4-6-10-18 progression your average bust will be 15 units and when you play the 1-2-3-5-9 progression your average bust will be 8 units.
LETS SEE WHAT WILL HAPPEN PLAYING THIS WAY
Over ANY two segments you can either,
win and win
win and lose
lose and win
lose and lose
win and win = plus 45 units [ 30 and 15 ]
win and lose = plus 22 units [ 30 and -8 avg. ]
lose and lose = minus 30 units [ -15 avg. and -15 avg. ]
lose and win = plus 15 units [ -15 avg. and 30 ]
WHAT WILL HAPPEN IN THE LONG TERM [ RUN]
Wins AND losses in a row :
[ a 50/50 game ]
EXPECTED WINS IN A ROW [ sample only to 5 ]
1. 16 W-L [ 30 - 8 avg. = 22 ]
2. 8 W-W-L [ 30/15 - 15 avg. = 30 ]
3. 4 W-W W-L [ 30/15/30 - 8 avg. = 67 ]
4. 2 W-W-W-W-L [ 30/15/30/15 - 15 avg. = 75 ]
5. 1 W-W-W-W-W-L [ 30/15/30/15/30 - 8 avg. = 112 ]
1. 16 x 22 = 352
2. 8 x 30 = 240
3. 4 x 67 = 268
4. 2 x 75 = 150
5. 1 x 112 = 112
total = 1122
EXPECTED LOSS IN A ROW [ sample only to 5 ]
1. 16 L-W [ -15 avg. and plus 30 = 15 ]
2. 8 L-L-W [ -15 / -15 avg. and plus 30 = 0 ]
3. 4 L-L-L-W [ -15 / -15 / -15 avg. and plus 30 = - 15 ]
4. 2 L-L-L-L-W [ -15 / -15 / -15 / -15 avg. and plus 30 = - 30 ]
5. 1 L-L-L-L-L-W [ -15 / -15 / -15 / -15 / -15 avg. and plus 30 = - 45
1. 16 x 15 = 240
2. 8 x 0 = 0
3. 4 x -15 = -60
4. 2 x -30 = -60
5. 1 x -45 = -45
total = 75 [ plus 240 - 0 - 60 - 60 - 45 = plus 75
So if what is expected to happen happens and it will [ over the long run with little variation swings in the short run ] YOU CAN NOT LOSE
P.S. about the bar
When playing this way the bar will have just a slight influence on your play. When the pass line has a higher wager on it when the bar is rolled on the come out treat it as a lose and increase your wager following the rules and when you win on the pass line you will BREAK EVEN not win 1 unit.
BUT if when the bar was rolled on the come out roll and you had a higher wager on it and did not get paid for the don't pass win just REPEAT the wagers on the pass and don't pass line and when you win on the don't pass line you will also break even
George Herrlinger

See Bet Progressions for more methods.

* Legal Crap

Thread Rating:

Probably similar to 18.... what nevermind.
So this is basically a firebet. Are you saying if the point is a 6 and there is a 3 then the bonus bet is over, even though it was not a seven out? If so then this has got to be the worst bet in the house.

Yes, it pays for hitting fewer numbers. 5 numbers would pay 150 to 1, even if the bet ended. 4 paid less, and 3 barely paid anything.
To win the main prize, 1,000 to 1, yes, you'd hit the other 5 numbers then the point.
The bet is placed before the come-out roll. I can't remember the name of the bet - something like 'six-shooter bonus' or the like.
I'm still trying to figure out what the chances are of hitting those 5 numbers and the point again all in a row.

Even if you dodge the 2-3-7-11-12 all those times, it seems more likely than not that the point would change in the course of throwing all those other numbers. You have to hit the current point after you've got all 6 numbers marked, then, no matter how many times it might have changed during the hand?Babs, I'm pretty sure that you'd lose if you hit the point early... tantamount to hitting the same number twice.
Nobody has answered your question because you did not give us a complete set of rules and it probably requires a lot of time commitment. People get paid for this stuff. With that said, I think that this would require a simulation or a lot of math by hand. There are a limited number of win scenarios (200 maybe?) with any other sequence of six rolls (after setting the point) losing. I mean, if I understand this correctly, you have to hit all 5 other 'numbers' then the point... any other situation and the bet loses.
Hopefully someone gets interested in this. I'll keep thinking about it. This has got to be worse than the firebet, right?

Hi. Last month I went into a smaller casino and found their craps table was closed. They did, however, happen to have a large 'craps machine' that was basically 6 seats with screens for betting, and a large dome that contained 2 large dice that would roll when the platform they were on started vibrating.

This sounds like the interblock 'organic craps' I have seen and played a few times.
There were 3 dice in the shaker I do remember.
so with 2 dice maybe it is another game totally...
2 dice slot is the shoot-to-win craps and that is all over Vegas but I have yet to see the side bet.
The bet is called Lucky Shooter (Great name for a XXX rated flick) from Interblock's site
This is what I found last year when it was warmer outside
'The Lucky Shooter is a side bet for Craps that will improve the Hold on the game.
The Side Bet can be made before each new “Come Out” roll.
The object
of the Lucky Shooter Side Bet is to first establish a Point,
then roll the 5 other Box Numbers (4, 5, 6, 8, 9, 10 excluding the Initial Point) in any order
during the next 5 rolls,
and then roll the “Initial Point” on the 6th roll.
Once one of the “5 other Box Numbers” is rolled it cannot be rolled again.
If a 7 or 11 is rolled on the Come Out Roll, the game ends and the bet remains working for the next Come Out roll.
If a 2, 3 or 12 is rolled on the Come Out Roll,
the game ends and the bet loses.
If a point is established on the Come Out Roll, the game ends when Any Number other than one of the remaining (not already rolled) “5 other Box Numbers” is rolled.
If all “5 other Box Numbers” are rolled, then the game ends after the 6th and final roll. The Player has a chance to win up to 1000 to 1.'

My question is, what are the odds or chances of actually winning the bonus bet like that?
Hitting all 6 required numbers within 6 rolls after the come-out.

I get (with simple multiply and adding in a 207x207 transition matrix in old Excel 2007) about 1 in 7,558.27

Craps Place Bet Odds

for what I call the Lucky6
for some to see
I B in Palm Desert (just next to Palm Springs)
for the long weekend and I plan on visiting Fantasy Springs Casino in Indio (plug) as they told me they have the bet there.
Hope it is the 1000 for 1 as I have seen the 500 for 1 paytable too.
I B very lucky this year (so far so goooooooood)
and I should hit that Lucky6 after dinner and dancing and B4 sex.
sounds like you had fun getting lucky!
SallyI get winning the 6-number bet 1 time in 7558.272